Question

A driver in a car speeding to the right at 24m/s suddenly hits the brakes and goes into a skid, finally coming to rest. The coefficient of static and kinetic friction between the tires and the road are s = .8 and k = 0.7. How far does the car skid?

Answer 1

42 m

Step-by-step explanation:

`v_(o)` = initial velocity of the car = 24 m/s

`v_(f)` = final velocity of the car = 0 m/s

μ = coefficient of kinetic friction = 0.7

g = acceleration due to gravity = 9.8 m/s²

a = acceleration due to kinetic frictional force = - μg = - (0.7)(9.8) = - 6.86 m/s²

d = distance through which the car skids

Using the kinematics equation

`v_(f)^(2) = v_(o)^(2) + 2 a d`

Inserting the values

`0^(2) = 24^(2) + 2 (- 6.86) d`

d = 42 m