Answer: 720
Explanation:
Given : Number of performers who will present their comedy acts = 7
If one of the performers insists on being the last stand-up comic of the evening and performer's request is granted, then its position got fixed.
Now, the remaining performers = 6
Now , the number of different ways to schedule the appearances is given by :-
![6!=6*5*4*3*2*1=720](https://img.qammunity.org/2020/formulas/mathematics/high-school/xe5b1rk2gs767374az07e70qamsfze6e7x.png)
Hence, the number of different ways to schedule the appearances =720