Question

pendulum is suspended from the ceiling of a stationary elevator, and the period is measured. If the elevator moves with constant velocity, does the period (a) increase, (b) decrease, or (c) remain the same? If the elevator accelerates upward, does the period (a) increase, (b) decrease, or (c) remain the same?

Answer 1

option (c)

option (b)

Step-by-step explanation:

The formula for the time period of simple pendulum is given by

`T =2\pi \sqrt{(L)/(g)}`

Where, L be the effective length of the pendulum and g be the acceleration due to gravity acting on the pendulum.

(i) As the elevator moves with constant velocity, then there is no change in the value of g so the period remains same. option (c)

(ii) If the elevator accelerates upwards, the acceleration acting on the pendulum increases and then the time period of the pendulum decreases.

option (b)