Question

A conductor is formed into a loop that encloses an area of 1.0 m2. The loop is orientedat a 30.0° angle with the xy-plane. A varying magnetic field is oriented parallel to thez-axis. If the maximum emf induced in the loop is 25.0 V, what is the maximum rate atwhich the magnetic field strength is changing

Answer 1

29 T/s

Step-by-step explanation:

Given:

Area enclosed by loop, A = 1 m²

Maximum induced emf, e = 25.0 V

loop is oriented at an angle 30° with the x-y plane.

varying magnetic field is oriented parallel to z-axis.

we have to find
`(dB)/(dt)_(max)`

Induced emf is given by:

`e =-A.cos\theta .(dB)/(dt)\\ \Rightarrow (dB)/(dt)=-(e)/(Acos\theta) = -(25)/(1* cos30^o) = -28.86T/s`≈29T/s