Question

Light from a helium-neon laser (wavelength 633 nm) passes through a 0.5 mm diameter hole. How far away should a viewing screen be placed to observe a diffraction pattern whose central maximum is 3.0 mm in diameter ?

Answer 1

L = 0.97 m

Step-by-step explanation:

Given

wavelength of light λ = 633 nm

Diameter of the hole d = 0.5 mm

Diameter of the central maxima D = 3.0 mm

To find

Distance of the screen L = ? m

Solution

`D=(2.44 * \lambda L)/(d) \\L= (d * D)/(2.44 * \lambda) \\L= (0.0005 * 0.003)/(2.44 * 633 * 10^(-9) ) \\L = 0.97 m`