Question

At the equator, near the surface of Earth, the magnetic field is approximately 80.0 μT northward and the electric field is about 150 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron with instantaneous velocity of 6.00 106 m/s directed to the east in this environment.

Answer 1

Gravitational force = 89.18 x 10^-31 N

Electric force = 2.4 x 10^-17 N

Magnetic force = 7.68 x 10^-17 N

Step-by-step explanation:

B = 80 micro tesla = 80 x 10^-6 T north

E = 150 N/C downward

v = 6 x 10^6 m/s east

Gravitational force = m g = 9.1 x 10^-31 x 9.8 = 89.18 x 10^-31 N

Electric force = q E = 1.6 x 10^-19 x 150 = 2.4 x 10^-17 N

Magnetic force = q v B Sin 90 = 1.6 x 10^-19 x 6 x 10^6 x 80 x 10^-6

= 7.68 x 10^-17 N