Answer:
0.132 m
Step-by-step explanation:
= mass of the ion = 5.29 x 10⁻²⁷ kg
= magnitude of charge on singly charged ion = 1.6 x 10⁻¹⁹ C
= radius of circular path followed by singly charged ion
= speed of the ion = 1.13 x 10⁶ m/s
= magnitude of the magnetic field = 0.283 T
Radius of the circular path is given as


= 0.132 m