Question

Two ions with masses of 5.29×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is 0.283 T. Each has a speed of 1.13 × 106 m/s, but one ion is singly charged and the other is doubly charged. Find the radius of the circular path followed by the singly charged ion in the field

Answer 1

0.132 m

Step-by-step explanation:

`m` = mass of the ion = 5.29 x 10⁻²⁷ kg

`q` = magnitude of charge on singly charged ion = 1.6 x 10⁻¹⁹ C

`r` = radius of circular path followed by singly charged ion

`v` = speed of the ion = 1.13 x 10⁶ m/s

`B` = magnitude of the magnetic field = 0.283 T

Radius of the circular path is given as

`r = (mv)/(qB)`

`r = ((5.29* 10^(-27))(1.13* 10^(6)))/((1.6* 10^(-19))(0.283))`

`r` = 0.132 m