Answer:
Temperature change in the wire is 625°C
Step-by-step explanation:
Let the initial current in the wire be I₀
Thus,
the final current in the wire will be, I = (1 - 0.20) × I₀ = 0.80I₀
Given α = 0.0004 1/°C
Now,
Resistance = (potential difference (E))/current (I)
also
R = R₀ [1 + αΔT]
Where ΔT is the increase in temperature , thus
E/I = E/I₀ [1 + α × ΔT)
on substituting the values in the above equation, we get
1/(0.80I₀) = 1/(I₀) × [1 + 0.0004 × ΔT]
or
1/(0.80) = [1 + 0.0004 × ΔT)]
or
ΔT = 625°C