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The decomposition of hydrogen peroxide follows first order kinetics and has a rate constant of 2.54 x 10-4 s-1 at a certain temperature. If the concentration of hydrogen peroxide is 0.321 M after 855 s , what was the initial concentration of hydrogen peroxide at this temperature?0.258 M0.399 M0.538 M0.677 M1.48 M

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Answer: The initial concentration of hydrogen peroxide at the given temperature is 0.399 M

Step-by-step explanation:

Decomposition of hydrogen peroxide is following first order kinetics.

Rate law expression for first order kinetics is given by the equation:


k=(2.303)/(t)\log([A_o])/([A])

where,

k = rate constant =
2.54* 10^(-4)s^(-1)

t = time taken for decay process = 855 s


[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process = 0.321 M

Putting values in above equation, we get:


2.54* 10^(-4)s^(-1)=(2.303)/(855s)\log ([A_o])/(0.321)


[A_o]=0.399M

Hence, the initial concentration of hydrogen peroxide at the given temperature is 0.399 M

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