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Determine the electrical and gravitational forces that two protons in the nucleus of a helium atom exert on each other when separated by 3.0×10−15m. Express your answer to two significant figures and include the appropriate units (G = 6.67 × 10-11 N ∙ m2/kg2, Mproton = 1.6726231 × 10-27 kg, Qproton, 1.6021 × 10-19 C K = 9 × 109 N ∙ m2/C2)

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Answer:

Fe = 25.67 N

Fg = 2.0734 x 10^-35 N

Step-by-step explanation:

r = 3 x 10^-15 m

G = 6.67 x 10^-11 Nm^2/kg^2

Mp = 1.6726231 x 10^-27 kg

Qp = 1.6021 x 10^-19 C

K = 9 x 10^9 Nm^2/C^2

The formula for the electrical force between the two protons is given by


F = K (Q_(p)* Q_(p))/(r^(2))


F = (9* 10^(9)* 1.6021* 10^(-19)* 1.6021* 10^(-19))/(3* 10^(-15)* 3* 10^(-15))

Fe = 25.67 N

The formula for the gravitational force between the two protons is given by


F = G (M_(p)* M_(p))/(r^(2))


F = (6.67* 10^(-11)* 1.6726231* 10^(-27)* 1.6726231* 10^(-27))/(3* 10^(-15)* 3* 10^(-15))

Fg = 2.0734 x 10^-35 N

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