Question

A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving in the same direction at vTi 5 20.0 m/s (Fig. P9.22). The velocity of the car immediately after the collision is vCf 5 18.0 m/s to the east. (a) What is the velocity of the truck immediately after the colli

Answer 1

The velocity of the truck after the collision is 20.93 m/s

Step-by-step explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car,
`v_(Ci)=25\ m/s`

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck,
`v_(Ti)=20\ m/s`

After the collision, velocity of the car,
`v_(Cf)=18\ m/s`

Let
`v` is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

`initial\ momentum=final\ momentum`

`1200\ kg* 25\ m/s+9000\ kg* 20\ m/s=1200\ kg* 18+9000\ kg* v`

`210000-21600=9000\ kg* v`

`v=20.93\ m/s`

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.