Answer:
0.7 kg m²
Step-by-step explanation:
F = force exerted applied by muscle in a professional boxer = 2551 N
r = length of lever arm = 3.15 cm = 0.0315 m
α = angular acceleration of the forearm = 115 rad/s²
I = moment of inertia of the boxer's forearm
τ = Torque applied by muscle in a professional boxer
Torque is given as
τ = I α = r F
Inserting the values
I (115) = (0.0315) (2551)
I = 0.7 kg m²