Question

When a charged capacitor is connected to an inductor, the value of the charge on the capacitor oscillates and so does the current in the circuit. What changes in the current would take place if the same capacitor, with the same initial charge, is connected to a inductor with a larger inductance?

Answer 1

If inductor is replaced by larger value then the angular frequency will decrease and the amplitude of current will also decrease

Step-by-step explanation:

As we know that when charged capacitor is connected to an inductor without any resistance then in that case energy loss would be zero and charge on capacitor will change to and fro from capacitor to inductor

The energy equation is given as

`(1)/(2)Li^2 + (q^2)/(2C) = (Q^2)/(2C)`

here we know

i = current at any instant of time

q = charge at any instant of time

Q = initial total charge on capacitor

So here charge will oscillate from capacitor to inductor and the equation is given as

`q = Q sin(\omega t + \phi)`

here we know

`\omega = (1)/(√(LC))`

now the current in the circuit is given as

`i = (dq)/(dt) = (Q)/(√(LC))cos(\omega t + \phi)`

now we can say that inductor is replaced by larger value then the angular frequency will decrease and the amplitude of current will also decrease