Question

Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium concentration of H2O(g). C2H4(g) + H2O(g) ↔ C2H5OH(g) Kc = 9.0 × 103 [C2H4]eq = 0.015 M [C2H5OH]eq = 1.69 M

Answer 1

Answer: The equilibrium concentration of H2O(g) is 12.52 x
`10^(-3)`

Explanation: The given equilibrium reaction is -

`C_(2)H_(4)(g) + H_(2)O(g) \rightleftharpoons  C_(2)H_(5)OH(g)`

Equilibrium constant is the ratio of concentration of the products to the reactants.

Mathematically, it can be written as-

Kc =
`[C_(2)H_(5)OH(g)]` /
`[C_(2)H_(4)]`
`[H_(2)O]`

Given values are -

Kc = 9.0 x
`10^(3)`

`[C_(2)H_(5)OH(g)]` = 1.69M

`[C_(2)H_(4)]` = 0.015M

Susbtituting these values in the equation we get

9.0 x
`10^(3)` = 1.69M / 0.015M
`[H_(2)O]`

`[H_(2)O]` = 1.69M / 0.015M x 9.0 x
`10^(3)`

`[H_(2)O]` = 12.52 x
`10^(-3)`