Question

A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 25.0 m/s. A net is positioned a horizontal distance of 50.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?

Answer 1

`10.8`meters

Explanation:

The horizontal distance traveled is equal to
`50`

velocity in the horizontal direction
`= 25* cos(45)(m)/(s)`

Time taken to travel is horizontal distance

`= (50)/(25*cos(45))\\ = 2.83`seconds

The vertical height is given by

`Y = v_i*t+ (1)/(2) a*t^2`

where

`v_i=`initial velocity

`a=`acceleration due to gravity

Substituting the given values in above equation, we get -

`Y = (25 * sin(45))* 2.83+(1)/(2) * 9.8* 2.83*2\\Y = 10.8`meter