Question

20. A car battery with a 12-V emf and an internal resistance of 0.050 Ω is being charged with a current of 60 A. Note that in this process, the battery is being charged. (a) What is the potential difference across its terminals? (b) At what rate is thermal energy being dissipated in the battery? (c) At what rate is electric energy being converted into chemical energy

Answer 1

Part a)

V = 15 Volts

Part b)

P = 180 Watt

Part c)

Rate = 720 Watt

Step-by-step explanation:

Part a)

When battery is in charging then the potential difference of the terminals of cell is given by

`\Delta V = EMF + iR`

here we know that

EMF = 12 volts

i = 60 A

r = 0.050 ohm

now we have

`\Delta V = 12 + (0.050)(60) = 15 Volts`

Part b)

Rate of thermal energy dissipated is the energy which is dissipating across the resistor

so here we have

`P = i^2 R`

`P = (60^2)(0.05)`

P = 180 Watt

Part c)

Rate at which Energy stored inside the cell is the rate of electrical energy that is converted into the chemical energy

`Rate = EMF * i`

`Rate = (12)(60)`

`Rate = 720 Watt`