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A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The upper face carries +95.0 nC/m2 while the lower face carries -25.0 nC/ m2. What is the magnitude of the electric field at a point within the sheet 2.00 cm below the upper face? (ε0 = 8.85 × 10-12 C2/N ∙ m2)

User Jlembke
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1 Answer

5 votes

Answer:


E = 6.77 *10^(3) N/C

Step-by-step explanation:

THE GIVEN sheet can be taken as two horizontal force with surface charge density is

at one surface is ∈_1 =
95*10^ {-9} C/mm2

at oher surface is ∈_2=
-25*10^(-9) C/mm2

the magnitude of electric field due to surface charge is given as
(∈)/(2∈_O)

So, electric field at P (2 CM below from surface is) = E_1 +E_2


E = (∈_1)/(2∈_O) +(∈_2)/(2∈_O)


E = (95*10^(-9) +25*10^(-9))/(2*8.85*10^(-12))


E = 6.77 *10^(3) N/C

User Toine Db
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