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Three friends went to the fair. Michelle ate three hot dogs, one pretzel, and two snow cones. She spent $25. Amanda ate two hot dogs, three pretzels, and three snow cones. She spent $30. Lucas ate two hot dogs, two pretzels, and four snow cones. He spent $25. Which system of equations matches the friends' night at the fair?

User Mozzbozz
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2 Answers

2 votes

Answer:

3x + y + 2z = 25

2x + 3y + 3z = 30

2x + 2y + 4z = 25

Explanation:

Let x, y and z represent the price ( in dollars ) of each hot dog, each pretzel and each snow cones respectively,

So, Price of 3 hot dogs, 1 pretzel, and 2 snow cones = 3x + y + 2z,

Price of 2 hot dogs, 3 pretzels, and 3 snow cones = 2x + 3y + 3z

And, price of 2 hot dogs, 2 pretzels, and 4 snow cones = 2x + 2y + 4z

According to the question,

3x + y + 2z = 25

2x + 3y + 3z = 30

2x + 2y + 4z = 25

Which is the required system of equations.

User Gausie
by
7.8k points
3 votes

Answer:

The system of equations is


3x+y+2z=25


2x+3y+3z=30


2x+2y+4z=25

Explanation:

Let

x ----> the cost of one hot dog

y ----> the cost of one pretzel

z ---> the cost of one snow cones

we know that

The system of equations that represent this situation is

Michelle


3x+y+2z=25 -----> equation A

Amanda


2x+3y+3z=30 -----> equation B

Lucas


2x+2y+4z=25 -----> equation C

User Jaltiere
by
8.2k points