The equation that reveals the minimum value for the equation is 2(x + 3)² = 32
Which reveals the minimum value for the equation
From the question, we have the following parameters that can be used in our computation:
2x² + 12x − 14 = 0
Rewrite as
2x² + 12x = 14
So, we have
2(x² + 6x) = 14
Take the coefficient of x
k = 6
Divide by 2
k/2 = 3
Square both sides
(k/2)² = 9
So, we have
2(x² + 6x + 9) = 14 + 2 * 9
2(x² + 6x + 9) = 32
Express as squares
2(x + 3)² = 32
Hence, the equation that reveals the minimum value for the equation is 2(x + 3)² = 32
Question
Which of the following reveals the minimum value for the equation 2x^2 + 12x - 14 = 0?
2(x + 6)^2 = 26
2(x + 6)^2 = 20
2(x + 3)^2 = 32