Answer:
45 m
Explanation:
At the time of launch, the time x = 0
Substitute x = 0 into h(x)
h(0) = - 5 (0 + 1)(0 - 9) = - 5(1)(- 9) = - 5 × - 9 = 45
45 meters
If x represents the seconds after the launch, then the time of launch is when x=0 so you just need to solve for h(0)
h(0) = -5(1)(-9)
h(0) = 45
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