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Find all the real zeros of

f(x)=3x^3-9x^2+3x-9


Can someone help me please

1 Answer

2 votes

Answer:

x=0,3

Explanation:

start by dividing every term by 3

x^3-3x^2+x-3

group into 2 terms

(x^3-3x^2)+(x-3)

simplify as much as you can

x^2(x-3)+(x-3)

combine terms

(x^2)(x-3)

x=3, 0

User Ram Sharma
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