Question

A gas is stored in a cylinder at a pressure of 6.0x10^5 N/m^2 and at a temperature of 10°C will be the change of the volume of the gas at 35° C if the pressure of the gars does not change?

Answer 1

0.34 x 10^-3 m^3

Step-by-step explanation:

P1 = 6 x 10^5 N/m^2

T1 = 10 degree C = 10 + 273 = 283 K

T2 = 35 degree c = 35 + 273 = 308 K

Pressure remains constant , P2 = P1

P1 V1 = R T1

V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3

Now, let the Volume is V2

P1 V2 = R T2

V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3

Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3