Question

Without the wheels, a bicycle frame has a mass of 6.71 kg. Each of the wheels can be roughly modeled as a uniform solid disk with a mass of 0.820 kg and a radius of 0.343 m. Find the kinetic energy of the whole bicycle when it is moving forward at 3.22 m/s.

Answer 1

Answer:43.311 J

Step-by-step explanation:

Given

mass of frame
`\left ( m_f\right )=6.71 kg`

mass of wheel
`\left ( m_w\right )=0.820 kg`

radius of wheel
`\left ( r\right )=0.343 m`

v=3.22 m/s

Moment of inertia of each wheel\left ( I\right )=\frac{1}{2}mr^2[/tex]

`I=0.0482 kg-m^2`

kinetic Energy of whole cycle=Kinetic energy of wheels and frame+rotational energy of Wheels

`K.E.=(1)/(2)\left ( m_f+m_w\right )v^2+2* (1)/(2)I\omega ^2`

`K.E.=(1)/(2)\left ( 6.71+0.820\right )3.22^2+2* (1)/(2)0.0482* \left ( (3.22)/(0.343)\right )^2`

K.E.=39.037+4.274=43.311J