Answer:
(a) 3.0 μF
(b) 75.0 μF
Step-by-step explanation:
The equivalent capacitance when the capacitors are connected all in series is:

Where
is the equivalent capacitance,
,
,
,
and
are the capacitance of each capacitors. In this case, they all have 15.0 μF. So we can replace as:


The solve for
:
=3.0 μF
The equivalent capacitance when the capacitors are connected all in parallel is:

Replacing values we get:
=15.0 μF+15.0 μF+15.0 μF+15.0 μF+15.0 μF
=75.0 μF