Step-by-step explanation:
it is given that,
Frequency of AC generator, f = 60 Hz
Magnetic field, B = 0.12 T
Area of the coil, A = 0.03 m²
Peak out put, V = 270 V
Resistance of the coil, R = 04 ohms
1. Let N is the number of loops the coil must contain. The peak voltage of AC generator is given by :



N = 199
2. Applying Ohm's law as :


I = 675 A
3. Power,


P = 182250 watts
Hence, this is the required solution.