Question

Objects with masses of 135 kg and a 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects on a 38.0-kg object placed midway between them.

Answer 1

The net gravitational force on the mass is
`1.27* 10^(-5)`

Step-by-step explanation:

We have by Newton's law of gravity the force of attraction between masses
`m_(1),m_(2)`

`F_(att)=G(m_(1)m_(2))/(r^(2))`

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

`F_(1)=6.67* 10^(-11)(135* 38)/((0.25)^(2))\\\\F_(1)=5.47* 10^(-6)N`

Force of attraction between 435 kg mass and 38 kg mass is

`F_(2)=6.67* 10^(-11)(435* 38)/((0.25)^(2))\\\\F_(2)=1.76* 10^(-5)N`

Thus the net force on mass 38.0 kg is
`F_(2)-F_(1)=1.76* 10^(-5)-5.47* 10^(-6)\\\\F_(2)-F_(1)=1.27* 10^(-5)`