Answer:
The area of rectangle EFGH is
![242\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/c7y2u72lmpa3qoa9nh72wcyyga90heli8a.png)
Explanation:
For this problem I assume that rectangle ABCD and rectangle EFGH are similar
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
Let
z ------> the scale factor
The scale factor is the ratio between the diagonals of rectangles
so
![z=(22)/(12)=(11)/(6)](https://img.qammunity.org/2020/formulas/mathematics/high-school/u0d1rjrghi52jmi3l33tf41p41bsthwagl.png)
step 2
Find the area of rectangle EFGH
we know that
If two figures are similar, then the ratio of its areas is the scale factor squared
Let
z------> the scale factor
x -----> area of rectangle EFGH
y ----> area of rectangle ABCD
so
![z^(2)=(x)/(y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bsr5zpx86e0gikgp398wuhrw2lup269tnz.png)
we have
![z=(11)/(6)](https://img.qammunity.org/2020/formulas/mathematics/high-school/fzo7u6qg3qq4inrxsnqf3ae4j9pqforu4x.png)
![y=72\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8xm7r7aurpodsym773q4p1lkievhlgjafl.png)
substitute and solve for x
![((11)/(6))^(2)=(x)/(72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/isocy32t0wfshymagri4etli7oygrs8qta.png)
![(121)/(36)=(x)/(72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/cwydpzcf5hyj0y1sqw3i3mke6bbbi27wbh.png)
![x=(121)/(36)(72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6efavojd8payio3uxvlx8bsth2c8ouxpri.png)
![x=242\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/cfppn72gxefuz4bwd67ip369n4s80xxs6o.png)