Question

You and a friend try to move a 50.0 kg box over a smooth floor (no friction). You push down and right with a force 30.0 N, at angle of 20 degrees below the horizontal. Your friend ties a rope to the front of the box and pulls with a 25.0 N force, at an angle 30 degrees above the horizontal. What is the acceleration of the box in the horizontal direction? Assuming the box does not move in the vertical direction, what is the normal force on the box?

Answer 1

Answer:
`0.996 m/s^2`

Step-by-step explanation:

Forces in horizontal direction will move the block

30N cos component and 25 cos component will accelerate block

30cos20+25cos30=50a

21.65+28.19=50a

`a=(49.84)/(50)`

`a=0.996 m/s^2`