Answer:
F = 2625 N
Step-by-step explanation:
let F be the force required to bring the car to stop, Ф be the angle between the force and the path of the motion,X be the distance it takes the car to come a complete stop, Kf be the final kinetic energy of the car and Ki be the kinetic energy of the car initially.
vi = 90.0/3.6 = 25 m/s
from Work and Energy, we know that:
Wtot = Kf - Ki
but Kf = 0J because the car's final velocity is 0 and W is the work done by the force F
W = -Ki = -1/2(m×vi^2)
F×X×cos(Ф) = -1/2(m×vi^2)
-F×X = -1/2(m×vi^2)
F = (1/2)[(m×vi^2)/X]
F = (1/2)[(1050×(25)^2)/125]
F = 2625 N
therefore, the force need to put the car to a complete stop is 2625 N.