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A spring has a spring constant k= 7.85 N/m. If the spring is displaced 0.230m from its equilibrium position, what is the magnitude of the force that the spring exerts?

User David Holm
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1 Answer

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The spring force is given by:

F = kΔx

F = spring force, k = spring constant, Δx = change in spring length

Given values:

k = 7.85N/m, Δx = 0.230m

Plug in and solve for F:

F = 7.85(0.230)

F = 1.81N

User Cusman
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