Question

On a certain game show, contestants spin a wheel when it is their turn. One contestant gives the wheel an initial angular speed of 3.40 rad/s. The angular acceleration of the wheel is -0.736 rad/s^2. Through what angle has the wheel turned when its angular speed is 2.10 rad/s ?

Answer 1

The wheel has turned θ= 4.84 rad when its angular speed is ωf= 2.1 rad/s

Step-by-step explanation:

ωi= 3.4 rad/s

ωf= 2.1 rad/s

α= - 0.736 rad/s²

ωf= ωi - α*t

(ωf-ωi)/α=t

t= 1.76 s

θ= ωi * t - α * t²/2

θ= 4.84 rad