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A tank of water has a length 10.0 m, width 5.00 m, and depth 2.50 m. What the absolute pressure at the bottom of the tank?

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Answer:

1.28 x 10^5 Pa

Step-by-step explanation:

The absolute pressure at the bottom of the tank of water is given by:


p= p_0 + \rho g h

where


p_0 = 1.03 \cdot 10^5 Pa is the atmospheric pressure


\rho = 1000 kg/m^3 is the water density

g = 9.8 m/s^2 is the acceleration of gravity

h = 2.50 m is the heigth of the column of water

Substituting into the formula, we find


p=1.03\cdot 10^5 +(1000)(9.8)(2.50)=1.28\cdot 10^5 Pa

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