Question

A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass? 

Answer 1

`c=0.2\ J/g^(\circ) C`

Step-by-step explanation:

Given that,

Mass of a glass, m = 4 g

Initial temperature,
`T_i=5^(\circ) C`

Final temperature,
`T_f=45^(\circ) C`

Heat absorbed, Q = 32 J

We need to find the specific heat of the glass. The formula for the heat absorbed is given by :

`Q=mc\Delta T\\\\c=(Q)/(m\Delta T)\\\\c=(32\ J)/(4\ g* (45-5)^(\circ) C)\\\\=0.2\ J/g^(\circ) C`

So, the required specific heat of the glass is
`0.2\ J/g^(\circ) C`.