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Y''-4y=cosx find general solution.

Y''-4y=cosx find general solution.
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Y''-4y=cosx find general solution.

User Ellemenno
by
7.5k points

1 Answer

5 votes

Answer:

Explanation:


y''-4y=cosx

The auxialary equation and solutions are as follows:


m^2-4=0\\m=2,-2

General solution is


y=Ae^(2x) +Be^(-2x)

Right side =cosx

Particular Integral

=
(cosx)/(-1-4) =(-cosx)/(5)

Hence full solution is

User Yannik
by
8.8k points
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