Question

Find the inverse laplace

F(s)=11/(s^2+9)^2

Answer 1

Explanation:

we have given F(s)=
`(11)/(\left ( s^2+9 \right )^2)`

`(11)/(\left ( s^2+9 \right )^2)` =
`(A)/(S^2+9)+(B)/(\left ( S^2+9 \right )^2)`

using partial fraction method

11= A
`S^2`+9A+B

on comparing A=0 and B=11

putting the value of A and B in function

F(s)=
`(11)/(\left ( s^2+9 \right )^2)`

now taking inverse laplace

f(t)=
`11te^(-9t)`