Answer: 4.54%
Explanation:
The binomial probability formula :-
, where P(x) is the probability of getting success in x trials, n is total number of trials and p is the probability of getting succes in each trial.
Given : The proportion of college freshmen majoring in business said that "to get training for a specific career" was a very important reason for their going to college :

Now, if six freshman business majors selected at random, then the probability that no more than two of the six freshmen in the group felt that this reason was very important. :-

Hence, the probability that no more than two of the six freshmen in the group felt that this reason was very important= 4.54 %