1.4k views
0 votes
Let f: R --> R Prove that f is continuous on R iff f-1(H) is a closed set whenever H is a closed set

User Evilcelery
by
7.5k points

1 Answer

6 votes

Answer with Step-by-step explanation:

We are given that a function is a continuous on R

f:R
\rightarrowR

We have to prove that if function is continuous ton R iff inverse image of closed set H is closed.

Let H be a closed set and function is continuous then R-H is a opens set


f^(-1)(R-H)=f^(-1)(R)-f^(-1)(H)=R-f^(-1)(H)=Open set

When function is continuous then inverse image of open set is open

Hence,
f^(-1)(H)is a closed set

Conversely,

Let inverse image of closed set H is closed

If H is closed set then R-H is open set


f^(-1)(R-H)=f^(-1)(R)-f^(-1)(H)=R-f^(-1)(H)

When inverse image of closed set is closed then R-inverse image of H is opens set

When inverse image of open set is open then the function is continuous.

Hence, function is continuous.

Hence proved.

User Ivan Ivanovich
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories