Answer with Step-by-step explanation:
We are given that a function is a continuous on R
f:R
R
We have to prove that if function is continuous ton R iff inverse image of closed set H is closed.
Let H be a closed set and function is continuous then R-H is a opens set
=Open set
When function is continuous then inverse image of open set is open
Hence,
is a closed set
Conversely,
Let inverse image of closed set H is closed
If H is closed set then R-H is open set
![f^(-1)(R-H)=f^(-1)(R)-f^(-1)(H)=R-f^(-1)(H)](https://img.qammunity.org/2020/formulas/mathematics/college/cad9y1n9dbqqwgxoi3q58190thtkax24xc.png)
When inverse image of closed set is closed then R-inverse image of H is opens set
When inverse image of open set is open then the function is continuous.
Hence, function is continuous.
Hence proved.