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(k/3^k)(x-6)^k

for this series determine whether it is convergent or not .If convergent find radius of convergence

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\displaystyle\sum_(k\ge0)\frac k{3^k}(x-6)^k

converges by the ratio test for


\displaystyle\lim_(k\to\infty)\left|\frac{(k+1)/(3^(k+1))(x-6)^(k+1)}{\frac k{3^k}(x-6)^k}\right|=\fracx-63\lim_(k\to\infty)\frac{k+1}k<1

The limit is 1, so the series converges as long as


\frac3<1\implies|x-6|<3

which indicates a radius of convergence of 3.

User Naumcho
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