Question

A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius , and the outer one a radius r2 = 8.0 mm. The common length of the cylinders is L = 150 m. What is the potential energy stored in this capacitor when a potential difference 4.0 V is applied between the inner and outer cylinder?

Answer 1

Answer:
`9.6* 10^(-8) J`

Step-by-step explanation:

The capacitance of cylindrical capacitor is

C=
`(2\pi \varepsilon _0L)/(\ln(r_2)/(r_1))`

C=
`(2\pi * 8.854* 10^(-12)* 150)/(\ln(8)/(4))`

C=
`1.2* 10^(-8) F`

potential Energy stored in capacitor=
`(1)/(2)CV^2`

=
`(1)/(2)* 1.2* 10^(-8)* 4^2`

=
`9.6* 10^(-8) J`