Question

A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on the box. Coefficient of sliding friction is 0.4

Answer 1

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80 N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Step-by-step explanation:

Answer 2

The acceleration of the block is 0.98 m/s².

Step-by-step explanation:

It is given that,

Weight of a box, W = 200 N

Horizontal force acting on the box, F = 100 N

Coefficient of sliding friction is 0.4

Net force acting on the box,
`F_(net)=F-\mu W`

`F_(net)=100-0.4* 200`

`F_(net)=20\ N`

Let a is the acceleration of the box. So,

`a=(F_(net))/(m)`

Since,
`m=(W)/(g)=(200)/(9.8)=20.40\ kg`

`a=(20)/(20.40)`

`a=0.98\ m/s^2`

So, the acceleration of the block is 0.98 m/s². Hence, this is the required solution.