Question

Lithium hydrogen carbonate, LiHCO3, decomposes when heated to form Li2O, CO2, and H2O. How many moles of H2O are formed when 0.50 mol LiHCO3 decomposes?

Answer 1

When 0.50 mol of lithium hydrogen carbonate (LiHCO3) decomposes, it produces 0.25 mol of water (H2O).

Step-by-step explanation:

You asked how many moles of H2O are formed when 0.50 mol LiHCO3 decomposes. The decomposition reaction for LiHCO3 to produce Li2O, CO2, and H2O is:

2 LiHCO3(s) → Li2O(s) + 2 CO2(g) + H2O(g)

According to the balanced equation, 2 moles of LiHCO3 produce 1 mole of H2O. Therefore, when 0.50 mole of LiHCO3 decomposes, you would get half of that ratio in moles of water:

(0.50 mol LiHCO3) / (2 mol LiHCO3) = 0.25 mol H2O

Therefore, the decomposition of 0.50 mol of LiHCO3 will produce 0.25 mol of H2O.

Answer 2

0.25 mol of water

Step-by-step explanation:

The starting point is writing out a balanced chemical equation

`2LiHCO_(3) --->Li_(2)O +2CO_(2) +H_(2)O`

From here we can see that 2 moles of Lithium hydrogen carbonate produce 1 mole of water. It follows that 0.5 moles of Lithium hydrogen carbonate will produce half of that too, which is 0.25 moles. The ratio is always mantained.