Question

. Consider the following reaction: CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g) A reaction mixture initially contains 0.50 M CH4 and 0.75 M H2S. If the equilibrium concentration of H2 is 0.44 M, find the equilibrium constant (Kc) for the reaction.

Answer 1

0.0376

Step-by-step explanation:

CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g)

start 0.5 0.75 0 0

change -0.11 -0.22 +0.11 +0.44

equilibrium 0.39 0.53 0.11 0.44

`K_(c)=(products)/(reactants) =([CS_(2)][H_(2)]^(4))/([CH_(4)][H_(2)S]^(2))=([0.11][0.44]^(4))/([0.39][0.53]^(2)) =0.0376`