Answer : The volume of stock solution will be, 215 ml
Solution :
According to the neutralization law,
![M_1V_1=M_2V_2](https://img.qammunity.org/2020/formulas/chemistry/high-school/e5m9q7izfcpl0dh31b032s9st1a7l0hywc.png)
where,
= molarity of HCl solution = 0.75 M
= volume of HCl solution = 575 ml
= molarity of stock solution = 2.0 M
= volume of stock solution = ?
Now put all the given values in the above law, we get the volume of stock solution.
![(0.75M)* (575ml)=(2.0M)* V_2](https://img.qammunity.org/2020/formulas/chemistry/high-school/6b3c8g1rr19l5zzupgazs0mrp2o9vz30q1.png)
![V_2=215ml](https://img.qammunity.org/2020/formulas/chemistry/high-school/a2y5gu8mr6ak5iswbu3j1hq83odx9bqv8m.png)
Therefore, the volume of stock solution will be, 215 ml