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A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total distance traveled by the bouncing ball.

1 Answer

4 votes

Answer:

d = 90 ft

Step-by-step explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say


h_2 = (4)/(5)h

so the distance covered is given as


d = h + 2((4)/(5)h) + 2((4)/(5))^2h + 2((4)/(5))^3h........

here we know that

h = 10 feet


d = h + 2((4)/(5)h)(1 + (4)/(5) + ((4)/(5))^2 + ...........)


d = 10 + 2((4)/(5)(10))((1)/(1 - (4)/(5)))


d = 90 ft

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