Answer:
Step-by-step explanation:
k_max = 26.9 w/mk
k_min = 22.33 w/mk
Step-by-step explanation:
a) the maximum thermal conductivity is given as
K_MAX = k_m v_m + k_p v_p
where k_m is thermal conductvitiy of metal
k_p is thermal conductvitiy of carbide
v_m = proportion of metal in the cement = 0.15
v_p = proportion of carbide in the cement = 0.85

= 66*0.15 + 20*0.85
k_max = 26.9 w/mk
b) the minimum thermal conductivity is given as

= \frac{20*66}{20*0.15 +66*0.85}
k_min = 22.33 w/mk