Question

Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 85 vol% carbide particles in a metal matrix. Assume thermal conductivities of 20 and 66 W/m-K for the carbide and metal, respectively.

Answer 1

Step-by-step explanation:

k_max = 26.9 w/mk

k_min = 22.33 w/mk

Step-by-step explanation:

a) the maximum thermal conductivity is given as

K_MAX = k_m v_m + k_p v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.15

v_p = proportion of carbide in the cement = 0.85

`K_MAX = k_m v_m + k_p v_p`

= 66*0.15 + 20*0.85

k_max = 26.9 w/mk

b) the minimum thermal conductivity is given as

`k_min = ( k_(carbide) *k_(metal))/(k_(metal) v_(carbide) +k_(carbide) v_(metal))`

= \frac{20*66}{20*0.15 +66*0.85}

k_min = 22.33 w/mk