Question

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = -20.5 kJ/mol?

Answer 1

The value of Q for this reaction at 298 K can be calculated using the equation Q = e^(-∆G/RT).

Step-by-step explanation:

The value of Q for this reaction at 298 K can be found by using the equation Q = e−∆G/RT. In this equation, ∆G is the standard free energy change, R is the gas constant, and T is the temperature in Kelvin. By substituting the given values (∆G = -20.5 kJ/mol, R = 8.3145 J/(mol·K), T = 298 K) into the equation, we can calculate the value of Q.