Question

PLEASE HELP ASAP WILL GIVE BLAINLY PTS

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Answer 1

`\large\boxed{C.\ (2x-20)/(x^2+6x-40)}`

Explanation:

`f(x)=(x-16)/(x^2+6x-40)=(x-16)/(x+10x-4x-40)=(x-16)/(x(x+10)-4(x+10))\\\\f(x)=(x-16)/((x-4)(x+10))\\\\g(x)=(1)/(x+10)\\\\f(x)+g(x)=(x-16)/((x-4)(x+10))+(1)/(x+10)=(x-16)/((x-4)(x+10))+(1(x-4))/((x-4)(x+10))\\\\=(x-16+x-4)/((x-4)(x+10))=(2x-20)/((x-4)(x+10))=(2x-20)/(x^2+6x-40)`