Question

Jupiter has a mass of about 318 times the mass of Earth and a diameter of about 11.2 times the diameter of Earth. The acceleration of a body falling near the surface of Jupiter is about A : 24.8 m/s2 B : 278 m/s2 C : 9.80 m/s2 D : 3.87 m/s2 E : 0.345 m/s2

Answer 1

(a) 24.8 m/
`src^2`

Step-by-step explanation:

acceleration due to gravity is given by
`g=(GM)/(R^2)=9.8 m/sec^2`

where G is gravitational constant M is mass of earth and R is radius of earth

it is given that mass of Jupiter is =318 M

and radius of earth =11.2 R

`g_(jupiter)=(318GM)/(11.2^2* R^2)=2.535* 9.8=24.84375 m/sec^2`

so the acceleration due to gravity at Jupiter is 24.8 m/
`sec^2` so option a will be correct answer