Question

What is the value of x?

Answer 1

`x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=√(1681)=41`

Answer 2

To solve this you must use Pythagorean theorem:

`a^(2) +b^(2) =c^(2)`

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 9

b = 40

c = x

^^^Plug these numbers into the theorem

`9^(2) +40^(2) =x^(2)`

simplify

81 + 1600 =
`x^(2)`

1681 =
`x^(2)`

To remove the square from x take the square root of both sides to get you...

41 = x

Hope this helped!

~Just a girl in love with Shawn Mendes