Question

Simplify each expression. 3a^2b^-4/12a^-2b-2

A. a^4/4b^2
B.1/4b^6
C.1/4a^-4b^2
D.a^4/4b^6

Second question is
v^3w^-3/-v^-6w^3
A.-1/-v^3
B.-v^9/-w^6
C.1/v^3
-v^9w^-6
I NEED IMMEDIATELY!! PLEASE HELP THANK YOU VERY MUUUCH

Answer 1

IT'S A THEN B

Explanation:

Answer 2

1) A. a^4/4b^2

2) -v^9w^-6

Explanation:

1)

given

3a^2b^-4/12a^-2b-2

`(3a^2b^(-4))/(12a^(-2)b^(-2))\\\\`

canceling common factor 3, we get

`(a^2b^(-4))/(4a^(-2)b^(-2))`

`=(b^(-4)a^(2-\left(-2\right)))/(4b^(-2))`
`=(b^(-4)a^(2-\left(-2\right)))/(4b^(-2))`

`=(a^4)/(4b^(-2-\left(-4\right)))`

`=(a^4)/(4b^2)`

2)

Given:

v^3w^-3/-v^-6w^3

`=-(v^3w^(-3))/(v^(-6)w^3)\\=(w^(-3)v^(3-\left(-6\right)))/(w^3)\\=(v^9w^(-3))/(w^3)\\=(v^9)/(w^(3-\left(-3\right)))\\=-(v^9)/(w^6)\\`

=-v^9w^-6 !